-
AuthorPosts
-
Harry
October 18, 2016 at 7:10 pmPost count: 0Hey ho,
I recently bought the DROK 600W 12A DC-Boost-Converter and received it today. It works just fine but I need a little bit of advice with the CC.
I bought this converter to load a Li-Ion battery with an capacity of 500Wh at 42V. To load that kind of battery there is a CC Phase required. For that phase the voltage has to be 42V and the current 4A. With an empty battery the converter should provide the 4A constantly but the voltage should fall down to the voltage of the battery but with the loading of the battery the voltage level should rise back to 42V.
Is it possible for this converter to provide that constand current? And how should I adjust the output current, just connect the output + and – ?
Also, is there some kind of datasheet or manual?
The reason why I’m asking this is, that I tried to simulate a CC phase with an adjustable resistor and it didn’t work. When I adjusted the output current to 4A and connected an 8OHm resistor at the output, the current went straight to 4A and the voltage dropped, but when I raised the resistance the voltage rised AND the current dropped. My understanding of CC was, that the current should stay at 4A until the voltage is back at 42V and only then the current should start to drop if the resistance is still rising.Thank you very much in advance 🙂
MfG HarryHello Harry,
Thank you for writing in.
Here the PDF file is the datasheet of the product, please check it.
DATASHEET_090089
Do you mean you want to use this boost converter to charge for your 500Wh at 42V voltage regulator and you need 42V 4A constant current output、
Could you please tell us the input voltage/current in your application?
With your help, we can find a solution more quickly.
Best regardsHarry
October 19, 2016 at 5:05 amPost count: 0Hello Harry,
Thank you for your quick reply.
Here is the adjusting mehtod for you:
Firstly, in case without load, adjusting the output voltage of the product to 42V, then counter-clockwise adjust the CC potentiometer to min.(the end), connencting the 42V battery and a ammeter, then gradually clockwise adjustthe CC potentiometer until the output current is 4A.
When the charging voltage of the 42V battery increase, the charging current will decrease.
And when you set up the output current of the product to 4A, the output current will be bot over 4A.
Please note that before connecting the battery to the product, the output current of the product must be set to be the min.(counter-clockwise adjust the CC potentiometer to the end), otherwise, the module will be burnt.
And it is recommended that you can apply a fan to dissipate heat.
Hope this is helpful to you.
Bets regardsHarry
October 20, 2016 at 9:57 amPost count: 0Thanks for the advice!
How big of an issue would it be if I don’t set the output current to the min. before connecting the load? Yesterday I played a bit with your product and turned it on and off without disconnecting the load and it endured quite fine.
Thanks for mentioning the fan cause I wanted to ask you if the fan output is somehow limited in terms of current. I have some 24V fans at work but they tend to pull about 1A when starting and about 0,5A when running.PS: Sry for the sloppy English, I’m not a native speaker but trying my best *g*
Hello Harry,
You’re welcome.
It is better that you can set the output current to the min. before connecting the load, otherwise, it will damage the module.
And the power supply for the fan is the 24V battery, not the converter, so it will not affect the output current of the converter.
Hope this it is useful to you.
Best regardsHarry
October 21, 2016 at 8:38 amPost count: 0Well, the problem would be that I want this device to run automatically by a Raspberry Pi. If something is connected to the output it should be loaded.
Would it be possible to replace the CC potentiometer with some kind of decade resistor to adjust the output current by connecting and disconnecting some resistors?
If so, could you tell me the range of the potentiometer and what the appropriate time would be to raise the current from 0A to 4A?
Clay
October 21, 2016 at 4:14 pmPost count: 0I have a DROK® 600W 12A DC Boost Voltage Converter 12-60V to 12-80V Step-up Power unit.
I have it powered with a 48VDC 7amp power supply, and want to have it step up to 56vdc for a unit that up to 40watt. What is required to make this work? With a load attached, I get the same output of 48.3vdc on input and output with v-resistors not changing anything for output.
Clay
October 22, 2016 at 2:35 pmPost count: 0Hello Harry,
The output current just need to be set once and then the value of the output current can be stored.
And the product cannot be connected to a load when you adjust the output current.
As your description, your application needs 4A constant current.
You can finish setting the output current firstly, then connect the product to the Raspberry Pi.
Best regards
Ludwig Steinkrug
November 10, 2016 at 8:17 amPost count: 0Hello Ludwig,
Thank you for your interest in our product.
Do you need a step up/boost converter or a step down/buck converter?
Could you please tell us more details of your need, such as the input/output voltage range, the load, the working environment?
With your help, we can recommend a more suitable product to you.
Looking forward to hearing from you.
Best regardsLudwig
November 14, 2016 at 8:15 amPost count: 0Hello Ludwig,
Thank you for your reply.
The product in this post is a boost converter which is not suitable for your need.
Besides, voltage converter cannot be parallel connected.
Here is a recommendation to you:
DROK® Shockproof DC/DC 30-60V 48V to 24V 22A 530W Step-down Voltage Regulator Buck Power Converter Waterproof Volt Power Supply Transformer for GPS navigator AutomotiveTechnical Parameters:
Input voltage: DC 48V (wide voltage range: DC30-60V, adjustable)
Output voltage: DC 24V(non-adjustable)
Output current: 22A
Output power: 530W
Conversion rate: 96%
Over-current protection: 22A
Over-temperature: 150℃
Dimension: 74×74×32mm
Wire length: 15cm(5.91”)
Product Features:
1. Adopts Adopts synchronous rectification technology, high conversion rate(above 902%), low heat and stable.
2. Multiple protection function: over-current protection, transient absorption of high voltage protection, over-heat protection, output short-circuit protection(even if the input is short-circuit, it will not produce any extra energy to cause the power supply over-heat or autoignition.)
3. Uses embedding technology, waterproof, dust-proof,moisture-proof, shock-proof and can be applied to various poor working condition.
4. With aluminum alloy shell, safe and better heat dissipation.
Wiring Instruction:
Red wire: Input+
Black wire: Input-
Yellow wire: Output+
Black wire: Output-
Application:
Electric motor, audio equipment, GPS navigator, air conditioner, electric fan, LED lights, LED vehicle display, solar battery and other industrial electric equipment.Hope this can help you.
Best regards -
AuthorPosts
DROK® 600W 12A DC-Boost-Converter Constant Current / Voltage 12-60V
2016-10-18T19:10:33+00:00
-
Harry
Post count: 0Harry
Post count: 0Harry
Post count: 0Harry
Post count: 0Clay
Post count: 0Clay
Post count: 0Ludwig Steinkrug
Post count: 0Ludwig
Post count: 0
